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hex2c.py: Adopt a maximum chunk size 

Large segments will be chunked into 32K blocks to they can be handled
seperate. Creating a maximum chunk size allows us to perform a few
tricks in the reloader by allowing us to overwrite parts of the reloader
whilst it is running!

Signed-off-by: Daniel Thompson <daniel@redfelineninja.org.uk>
This commit is contained in:
Daniel Thompson 2020-11-04 19:06:03 +00:00
parent 8e89e38175
commit 9dd793ff19
1 changed files with 11 additions and 2 deletions
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13
tools/hex2c.py
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@ -20,7 +20,16 @@ def generate_c(ihex):
print('};')
print()
for i, segment in enumerate(ihex.segments()):
segments = []
chunk = 32 * 1024
for (start, end) in ihex.segments():
while start + chunk < end:
segments.append((start, start + chunk))
start += chunk
if start < end:
segments.append((start, end))
for i, segment in enumerate(segments):
print(f'static const uint8_t segment{i}[] = {{', end='')
for j in range(segment[0], segment[1]):
@ -30,7 +39,7 @@ def generate_c(ihex):
print('\n};\n')
print(f'const struct segment segments[] = {{')
for i, segment in enumerate(ihex.segments()):
for i, segment in enumerate(segments):
sg = ihex.tobinarray(start=segment[0], end=segment[1]-1)
crc = binascii.crc32(sg)
print(f' 0x{segment[0]:08x}, 0x{segment[1]:08x}, 0x{crc:08x}, segment{i},')